A = 1/2 BH
A = 24 = 1/2 BH
24 * 2 = BH
48 = BH
H = B - 2
48 = B(B - 2)
B2 - 2B = 48
B2 - 2B - 48 = 0
(B - 8)(B + 6) = 0
B = 8 or -6
Since the base cannot be negative, the base is 8 and the height is 6 (8 - 2)
Since an isosceles triangle can be represented by two right triangles back to back, you can utilize the pythagorean theorum to solve this example. Specifically: 18cm/2 = 9cm = 1 leg of right triangle (A) 24cm = hypotenuse of right triangle (C) A squared + B squared = C squared Altitude = B = square root of (C squared - A squared) = approximately 19.875
It can't.
Anything greater than 24 cm. P = 2*L + 2*W, since the length is fixed at 24cm we have: 2*(24cm) +2*W > 96cm 2W > 96 - 48cm 2W > 48cm, or Width > 24cm. So any width greater than 24cm will make the perimeter >96cm. Obviously a width of 24cm wouldn't work since a polygon with all four sides equal would be a square and not a rectangle.
The circumference of a 24cm circle is: 75.4 cm(diameter x pi = circumference).
v=LWH (length x witdhx height) .16m x .24m x 1.4m = 0.06144 m2
24cm small 2
The answer is 576cm.
Since an isosceles triangle can be represented by two right triangles back to back, you can utilize the pythagorean theorum to solve this example. Specifically: 18cm/2 = 9cm = 1 leg of right triangle (A) 24cm = hypotenuse of right triangle (C) A squared + B squared = C squared Altitude = B = square root of (C squared - A squared) = approximately 19.875
P = 24cm
1/2*base*10 = 120 base*10 = 240 base = 24cm
It can't.
Correct.
The diagonal is 26cm
24 cm squared = 24 cm * 24 cm = 576 cm2 = 576/10000 m2 or 0.0576 m2
Anything greater than 24 cm. P = 2*L + 2*W, since the length is fixed at 24cm we have: 2*(24cm) +2*W > 96cm 2W > 96 - 48cm 2W > 48cm, or Width > 24cm. So any width greater than 24cm will make the perimeter >96cm. Obviously a width of 24cm wouldn't work since a polygon with all four sides equal would be a square and not a rectangle.
The slant height will be 25 cm
24cm each