Yes, the point 4,8 is on the line formed by the equation y = 2x
Yes if you mean: 2x+y = 4
The equation of a line with slope m through a point (x0, y0) has equation: y - y0 = m(x - x0) Thus the equation of the line with slope 2 through the point (4, -3) has equation: y - (-3) = 2(x - 4) → y + 3 = 2x - 8 → y = 2x - 11
(Geometry) y=2x+8
If you mean a slope of 2 and a point of (1, 4) then the equation is y = 2x+2
Point: (-3, 4) Slope: 2 Equation: y-4 = 2(x--3) => y = 2x+10
x = 4 and y = 7 which will satisfy both equations
Yes if you mean: 2x+y = 4
The equation of a line with slope m through a point (x0, y0) has equation: y - y0 = m(x - x0) Thus the equation of the line with slope 2 through the point (4, -3) has equation: y - (-3) = 2(x - 4) → y + 3 = 2x - 8 → y = 2x - 11
To determine which pair of points lies on the equation (3x - y = 2), substitute the coordinates of each point into the equation. For a point ((x, y)) to lie on the line, it must satisfy the equation when the values of (x) and (y) are plugged in. For example, the point ((1, 1)) does not satisfy the equation, but the point ((2, 4)) does, as substituting (x = 2) gives (3(2) - 4 = 2). Thus, you need to check the specific points provided to identify those that satisfy the equation.
(Geometry) y=2x+8
If you mean a slope of 2 and a point of (1, 4) then the equation is y = 2x+2
2x + 4 is an expression, not an equation. There can be no solution set for an expression.
To determine if the point (-4, 2) is a solution of the equation (3y - 2x = 14), we can substitute (x = -4) and (y = 2) into the equation. This gives us (3(2) - 2(-4) = 6 + 8 = 14). Since both sides are equal (14 = 14), the point (-4, 2) is indeed a solution of the equation.
Point: (-3, 4) Slope: 2 Equation: y-4 = 2(x--3) => y = 2x+10
2x 4 10 is not an equation.
2
2x - 4 = -10 2x = -10 +4 2x = -6 x = -3