Which equation describes the line with a slope of 2 and contains the point (4-3)?

Answer 1

The equation of a line with slope m through a point (x0, y0) has equation:

y - y0 = m(x - x0)

Thus the equation of the line with slope 2 through the point (4, -3) has equation:

y - (-3) = 2(x - 4)

→ y + 3 = 2x - 8

→ y = 2x - 11

Answer 2

You have y = mx + b and m value is 2. The ( 4, -3 ) point can be used to get b, the y-axis intercept.
The point ( 4, -3 ) gives you : y = -3 for x = 4

-3 = ( m or 2 ) ( 4 ) + b

-3 = 8 + b ------> b = -3 - 8 = - 11

The equation for the line is :

y = 2x - 11 <--------[ Answer]----------

Answer 3

It is 2 =( y -(-3))/(x-4). Accordingly, 2 = (y+3)/(x-4). 2x -8 = y + 3. The result is 2x - y = 11