4xy = 4(3)(-7) = - 84
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Answer is D.73
evaluate 2x4x2 in the mod 5 system
You need 2 full equations to answer that, or the number for x and what it equals. Without that information that is insolvable.
just put in the numberssinze x = 3 and y = 2then(4*3*2) - (3) = 21
4xy = 4(3)(-7) = - 84
4xy + 6xz When factorising algebraic expressions treat them just as ordinary numbers. Ascertain what the common factors are. The factors of 4xy are 2 x 2 x 'x' x y The factors of 6xz are 2 x 3 x 'x' x z The factors common to both expressions are 2 and 'x'. Therefore, 4xy + 6xz = 2x(2y + 3z)
It is 4xy.
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(x^2 + 2y)(x^3 - 2xy + y^3) = x^2(x^3 - 2xy + y^3) + 2y(x^3 - 2xy + y^3) Now, let's distribute each term: = x^2 * x^3 - x^2 * 2xy + x^2 * y^3 + 2y * x^3 - 2y * 2xy + 2y * y^3 Now, simplify each term: = x^5 - 2x^3y + x^2y^3 + 2x^3y - 4xy^2 + 2y^4 Now, combine like terms: = x^5 + x^2y^3 - 4xy^2 + 2y^4 So, the expanded form of (x^2 + 2y)(x^3 - 2xy + y^3) is x^5 + x^2y^3 - 4xy^2 + 2y^4.
It is 4xy.
It is 4xy.
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If you mean x = 3 then 8*3+2 = 26
4xy - 2y(x + 4) = 4xy - 2xy - 8y = 2xy - 8y = 2y(x - 4)
(2x2+4xy-3)-(x2-2xy-4)Answer: x2+6x+1