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Minnie Crist
Wiki User
∙ 7y agoWhen x = -3, x - 2 = -5.
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How do you Evaluate the expression X2 and y4?
It is x*x + y*y*y*y
How do you evaluate functions?
To evaluate a function means to replace the variable with some value, and calculate the value of the function. For example, in the parabola y = x2 (or, using functional notation, f(x) = x2), if you replace x with 10, and calculate x2, you are evaluating the function for that specific value.
How do you factor x2 2x-3?
x2 + 2x - 3 = (x + 3)(x - 1)
Factor 9 - x2?
9 - x2 will factor into (3 - x)(3 + x)
Evaluate the function fx equals -x2 plus 5 for x equals 4?
Interpreting the question as "evaluate f(x) = -x2 + 5 for x = 4". This is the same as asking "what is f(4)". To evaluate f(4) just replace each instance of the x in the definition of f(x) by the number 4: f(4) = -42 + 5. The result is -11.
What is a grouping factor for polynomial x3 ax 3a 3x2?
x3 + ax + 3a + 3x2 = x (x2 + a) + 3 (a + x2) = x (x2 + a) + 3 (x2 + a) = (x2 + a)(x + 3) Checking the work: x3 + ax + 3x2 + 3a or x3 + 3x2 + 3a + ax = x2 (x + 3) + a (3 + x) = x2 (x + 3) + a (x + 3) = (x + 3)(x2 + a)
How do you Evaluate the expression X2 and y4?
It is x*x + y*y*y*y
What is the factor of x2 - 9?
(x + 3)(x - 3)
How do you evaluate functions?
To evaluate a function means to replace the variable with some value, and calculate the value of the function. For example, in the parabola y = x2 (or, using functional notation, f(x) = x2), if you replace x with 10, and calculate x2, you are evaluating the function for that specific value.
How do you factor x3 plus x2-3x-3?
x3 + x2 - 3x - 3 x(x2 + x - 3) - 3
Who do you factor x2 x-12?
14
What is the answer to 9-x2?
7
Answer to -x2 equals x-6?
-x2 = x - 6 x2 + x - 6 = 0 (x - 2)(x + 3) = 0 x ∈ {-3, 2}
How do you factor x2 2x-3?
x2 + 2x - 3 = (x + 3)(x - 1)
What is the anti-derivative of sqrtx2-x?
f'(x) = (x2 - x)1/21. Add one to the exponent2. Divide step 1 by the exponent plus one= (x2 - x)1/2+1____________1/2 + 1= (x2 - x)3/2_________ 3/2= (2/3) (x2 - x)3/2 + CIt may also be written:[2(x2 - x)3/2 / 3] + CCheck:f(x) = (2/3) (x2 - x)3/2Using the chain rule:f'(x) = (2/3) (3/2) (x2 - x)3/2-1= (x2 - x)1/2
Let g(x) = 2x and h(x) = x2 + 4. Evaluate (h ∘ g)(−5)?
104
Factor 9 - x2?
9 - x2 will factor into (3 - x)(3 + x)
