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Evaluate x-2 when x = -3.
x = -3
Subtract 2 from both sides.
x - 2 = -3 - 2
x - 2 = -5
x2 + 6x + 12 = 0 x2 + 6x + 9 = -3 (x + 3)2 = -3 x + 3 = ± √-3 x = -3 ± i√3
x2 + 7x + 9 = 3 ∴ x2 + 7x + 6 = 0 ∴ (x + 6)(x + 1) = 0 ∴ x ∈ {-6, -1}
3 6
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc. Please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y2 of (x + y)2. Also, If y = x2 - x then what = 3? If y = x2 and - x = 3 then y = 6 is inconsistent with the equation of the function.
x2 - 8x + 15 = 0 can be factored as (x - 3)(x - 5) = 0 : This holds true when one or both of the terms in brackets equals zero. When x - 3 = 0 then x = 3 When x - 5 = 0 then x = 5.