(7-3)^2 plus (7-1)^2 = 16+36
You don't "solve" an expression. You can solve an equation; an expression can be simplified or otherwise manipulated, and if you know the value of "x" (in this case), you can evaluate its value.
The answer is b+1. Therefore the algebraic expression for this is b+1
You have to substitute a value for the letter variable in the expression. This is what we call evaluating the algebraic expression. An example would be 3x+1=7, when x=2.
14
When simplified it is just: 1
You don't "solve" an expression. You can solve an equation; an expression can be simplified or otherwise manipulated, and if you know the value of "x" (in this case), you can evaluate its value.
1/2w+2
b + 1 is b plus 1 as an algebraic expression.
3(10x + y) + 2x + 7y (multiply the 3 through the parentheses then combine like terms) = 30x + 3y + 2x + 7y = 32x + 10 y Evaluate an expression for some values of x and y, means to substitute those values into the expression, such that when x = 3 and y = 1 the value of the given expression is 106: 32x + 10y = 32(3) + 10(1) = 96 + 10 = 106
Put n = 1, 2, 3, 4 etc in the expression 5n + 2 and evaluate to get the sequence.
It evaluates to: 12+(-1)+(-1)+3 = 13
2!
xy + x + y + 1 is an expression, not an equation. An expression cannot be solved.
You cannot. What you have in the question is an expression. An expression cannot be proven. You need an equation (or inequality).
You have to substitute a value for the letter variable in the expression. This is what we call evaluating the algebraic expression. An example would be 3x+1=7, when x=2.
The answer is b+1. Therefore the algebraic expression for this is b+1
You have to substitute a value for the letter variable in the expression. This is what we call evaluating the algebraic expression. An example would be 3x+1=7, when x=2.