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X plus XY equals 8 solve for Y?
x+xy=8 xy=-x+8 y=-1+8/x
Factor 2 plus 2y plus x plus xy?
2+2y+x+xy=(x+2)(y+1)
What is 2 over X plus 1 over Y simplified they are fractions?
I understand you want [(2/x) + (1/y)] as a single fraction. The common denominator is (xy): 2/x = (2y)/(xy); and 1/y = x/(xy), so the answer is (2y + x) / (xy)
Let xy x plus 2y and let xy x - z. Solve the following system of equations for x y and z (xy)z 4 x plus (x(y2))(-z) -2 (xy)(-z) 2?
To solve the system of equations given by ( xy = x + 2y ) and ( xy = x - z ), we can start by equating the two expressions for ( xy ). Setting ( x + 2y = x - z ) gives us ( 2y + z = 0 ) or ( z = -2y ). Substituting ( z ) into the other equation leads to a system that can be solved for ( x ) and ( y ). However, without numerical values or additional equations, we cannot find unique solutions for ( x, y, ) and ( z ).
How do you solve 1 divided by x minus 1 divided by y equals 1 divided by z solve for z?
(1/x) - (1/y) = (1/z) Get the left-hand side over a common denominator:- (y-x)/xy = 1/z Take the reciprocal of both sides:- z = xy / (y-x)
X plus XY equals 8 solve for Y?
x+xy=8 xy=-x+8 y=-1+8/x
What are the factors of xy plus x plus y plus 1?
xy + x + y + 1 = (x + 1)(y + 1).
How do you factor x-y plus xy-1?
(x-y) + (xy - 1) = (x - 1)(y + 1)
How do you solve for x when y equals quantity x plus 2 divided by quantity x plus 10?
y=(x+2)/(x+10) xy+10y=x+2 xy-x=2-10y x(y-1)=2-10y x=(2-10y)/(y-1)
Factor 2 plus 2y plus x plus xy?
2+2y+x+xy=(x+2)(y+1)
Factor 2x squared plus 2x plus xy plus y?
4
What is the answer to xy-x plus 2y-2?
0
How do you solve 2 2y x xy?
To solve the given terms is almost impossible in the absence of any plus, minus and equality signs.
What is 2 over X plus 1 over Y simplified they are fractions?
I understand you want [(2/x) + (1/y)] as a single fraction. The common denominator is (xy): 2/x = (2y)/(xy); and 1/y = x/(xy), so the answer is (2y + x) / (xy)
Let xy x plus 2y and let xy x - z. Solve the following system of equations for x y and z (xy)z 4 x plus (x(y2))(-z) -2 (xy)(-z) 2?
To solve the system of equations given by ( xy = x + 2y ) and ( xy = x - z ), we can start by equating the two expressions for ( xy ). Setting ( x + 2y = x - z ) gives us ( 2y + z = 0 ) or ( z = -2y ). Substituting ( z ) into the other equation leads to a system that can be solved for ( x ) and ( y ). However, without numerical values or additional equations, we cannot find unique solutions for ( x, y, ) and ( z ).
How do you solve 1 divided by x minus 1 divided by y equals 1 divided by z solve for z?
(1/x) - (1/y) = (1/z) Get the left-hand side over a common denominator:- (y-x)/xy = 1/z Take the reciprocal of both sides:- z = xy / (y-x)
What is the inverse of y(2-x plus 3) plus 1?
The multiplicative inverse of 5y -xy + 1 is 1/5y -xy + 1 The additive inverse of 5y - xy + 1 is -5y + xy - 1
