x2 + 4x - 96 = (x - 8)(x + 12).
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
x2+4x-32 = (x-4)(x+8) when factored
x2 + 4x + 6 can not be factored. If you want, you can reduce it to an expression with a single x term by comleting the square: x2 + 4x + 6 = x2 + 4x + 4 + 2 = (x + 2)2 + 2
x2 + 4x - 60 factors into (x + 10)(x - 6). You can use the FOIL method to check your answers when you factor.
(x-1)(x-3)
(x+4) (x+6)
(6 - x)(2 + x)
x+5 is a factor of x2+4x-5 use synthetic division to learn that the other factor is x-1
y = x2 - 4x + 4 can be factored into y = (x-2)(x-2) The repeated factor is 2.
You can work this out with long division, by checking to see if (x2 - 1) is a factor of (2x4 + 4x3 - x2 + 4x - 3). It is. Unfortunately, the WikiAnswers system is somewhat limited in depicting things such as long division, so we won't be able to represent it here. In short though, (2x4 + 4x3 - x2 + 4x - 3) / (x2 + 1) is equal to 2x2 + 4x - 3. which means that: (x2 + 1) / (2x4 + 4x3 - x2 + 4x - 3) = (x2 + 1) / (x2 + 1)(2x2 + 4x - 3) = 1 / (2x2 + 4x - 3)
x2 + 4x + 3 =(x + 3) (x + 1)