If you mean: 9x2-36x+16 then it is not a perfect square because its discriminant is greater than zero
so 9x2 = -16. Doesnt work without going to imaginary numbers, x2 = -16/9 ie x = 4i/3
(3x + y)(3x - y)
-9x 2 -12x+5 =
-1
Factor: 9x2 - 25.
(3x + 4)(3x - 4)
(3x + 4)(3x + 4)
If the question could more exactly be phrased as, "What is the value of x when 9x2 - 16 = 0", the answer is, x = 4 or -4. This answer can be found by factoring 9x2 - 16 into (3x + 4)(3x - 4) and setting each factor equal to zero.
is 9x^2 + 4 prime factor
The GCF is 9.
9x2 + 9x - 10 =(3x - 2)(3x + 5)
If you mean: 9x2-36x+16 then it is not a perfect square because its discriminant is greater than zero
16? using 16, you have (3x2 + 4)(3x2 + 4) = 9x2 + 24x + 16
9x2
3x2(x2 - 3)
so 9x2 = -16. Doesnt work without going to imaginary numbers, x2 = -16/9 ie x = 4i/3