Factorising, we have, 9x2+ 30x + 25 = (3x + 5)2;thus, when y = 0, x = -1⅔. This tells us that the sole x-intercept of this function is at the vertex, (0, 1⅔).
16
y = 0 and x = 8.
Anything you like (as long as it is > -16 so that BC > 0). In a parallelogram, adjacent sides do not impose any restrictions on one another.
The discriminant is 0.
The discriminant is 0.
9x2+6x-7 = 0 Using the quadratic equation formula:- x = 0.6094757082 or x = -1.276142375
9x2 + 7x = 2 9x2 + 7x - 2 = 0 9x2 + 9x - 2x - 2 = 0 9x(x + 1) - 2(x + 1) = 0 (9x - 2)(x + 1) = 0 x ∈ {-1, 2/9}
k = -3; factors are (9x + 3)(x - 1)
(3x+4)(3x-4)=0 x=±4/3
9x2-9x = 0 x2-x = 0 x(x-1) = 0 x = 1 or x = 0
It can be simplified in the form of: 2x3+9x2-7x-34 = 0
It is: 0
Factorising, we have, 9x2+ 30x + 25 = (3x + 5)2;thus, when y = 0, x = -1⅔. This tells us that the sole x-intercept of this function is at the vertex, (0, 1⅔).
The discriminant of a quadratic ax2 + bx + c is b2 - 4ac; thus: the discriminant of -9x2 + 6x + 14 is 62 - 4 x -9 x 14 = 540
-2x+16 = 0 -2x = -16 x = 8
x=-1.6