so 9x2 = -16. Doesnt work without going to imaginary numbers, x2 = -16/9 ie x = 4i/3
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Factorising, we have, 9x2+ 30x + 25 = (3x + 5)2;thus, when y = 0, x = -1⅔. This tells us that the sole x-intercept of this function is at the vertex, (0, 1⅔).
16
y = 0 and x = 8.
Anything you like (as long as it is > -16 so that BC > 0). In a parallelogram, adjacent sides do not impose any restrictions on one another.
The discriminant is 0.