5x(3x + 1)
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you do 2 sets of parenthesis and check it. for example: w2(w squared)-7w-8 (w+1) (w-8) *if you add 1w and -8w you will get -7w, which is what they want you to get. and w & w multiply to get w2(w squared), which is also what the factoring wants. another example: 3w2 (3w squared)+2-8 (3w-4) (w+2) *same thing applies with 3w x w = 3w2, and -4 +2=2, which is the answer. use this theory in all of them, unless there is a greatest common factor (GCF).
2x2 - 72 would be factored into (2x - 12)(x + 6) or (2x + 12)(x - 6) To double check, multiply each pair: (2x - 12)(x + 6) = 2x2 + 12x - 12x - 72 = 2x2 - 72 (2x + 12)(x - 6) = 2x2 - 12x + 12 x - 72 = 2x2 - 72
If this is a question about factorisation check the signs. As it stands, it cannot be factorised.
The way to do this is get an expression equal to zero, then solve (in this case it's a quadratic), so either factor or use the quadratic equation. x2 + x - 56 = 0: Factors into: (x - 7)(x + 8) = 0, x = 7 & x = -8To factor, find two numbers which when added equal 1 (the coefficient of the x term) and when multiplied equal -56. So one of the numbers must be positive and the other negative. Factor pairs of 56 are (1,56) (2,28) (4,14) and (7,8). Seven & eight are one apart, so if the seven is negative, they will add to equal 1. If either of the binomial factors is zero, then the result is zero, so for (x-7)=0, {x=7} solves it, and for (x+8)=0, {x=-8} solves it. Check your answers in the original equation, to make sure you did it correctly:7^2 + 7 = 49 + 7 = 56 (check) (-8)^2 + -8 = 64 - 8 = 56 (check) STANLY WAS HERE
When factoring it is fairly easy to check your answer. Say we want to factor x2+9x+14=0 (x+7)(x+2)=0 now if we want to check then we can just multiply these together and we should get the original polynomial... x2+2x+7x+14=0 x2+9x+14=0