To factorise a polynomial completely, first look for the greatest common factor (GCF) of the terms and factor it out. Next, apply techniques such as grouping, using the difference of squares, or recognizing special patterns (like trinomials or perfect squares) to break down the remaining polynomial. Continue this process until you can no longer factor, resulting in a product of irreducible factors. Always check your work by expanding the factors to ensure you return to the original polynomial.
a²-a = a(a-1)
To factorise is to find the numbers that divide into the original number by only using prime numbers. For example factorise 20 = 2 times 2 times 5
you do (245x)
to put into brackets
The answer will depend on where the brackets are. In general the solution would be to expand all the brackets, combine like terms and then factorise.
6(t2s)
It is the opposite of Expanding The Brackets
-5
m(g-a)
qwertyuiopasdfjk
In the same way that you would factorise any other expressions that do not contain an equality sign depending on the expressions of which none have been given.
The answer depends on how good you are.You can either factorise the number completely and express it in terms of the exponents of its prime factors. Any prime with an exponent of 3 (or a multiple of 3) is a cube factor.A faster, but more demanding way is to see if 8, 27, 64 ... are factors.The answer depends on how good you are.You can either factorise the number completely and express it in terms of the exponents of its prime factors. Any prime with an exponent of 3 (or a multiple of 3) is a cube factor.A faster, but more demanding way is to see if 8, 27, 64 ... are factors.The answer depends on how good you are.You can either factorise the number completely and express it in terms of the exponents of its prime factors. Any prime with an exponent of 3 (or a multiple of 3) is a cube factor.A faster, but more demanding way is to see if 8, 27, 64 ... are factors.The answer depends on how good you are.You can either factorise the number completely and express it in terms of the exponents of its prime factors. Any prime with an exponent of 3 (or a multiple of 3) is a cube factor.A faster, but more demanding way is to see if 8, 27, 64 ... are factors.