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Q: Factor the trinomal -8x plus 3x2 - 3?

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(x + 1)(3x + 5)

3(x2-x-7)

In general, no.

two negative

x2+8x = -3x2+5 4x2+8x-5 = 0 (2x+5)(2x-1) = 0 x = -5/2 or x = 1/2

It cannot be done with whole numbers, but using irrational numbers it factorises into: 3x² + 8x + 1 = (1/3)(3x + (4 + √13))(3x + (4 - √13))

3x2 + 8x - 8 doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-4 plus or minus 2 times the square root of 10) divided by three.x = 0.7748517734455863x = -3.441518440112253

5 - 8x + 3x2 = 3x2 - 8x + 5 (since the sign of the second term is negative, then 5 can be factored as (-1)(-5)) = (3x - )(x - ) (try to put 1 or 5 to the empty places, in order to obtain -8x) = (3x - 5)(x - 1)

2x^2 + 8x + 3 = 0

The sum 6 (3x^2) + 8x -3 plus 3 (3x^2) - 7x + 2 = 27 x^2 + x -1

That does not factor neatly.

= (3x + 5)(x + 1) so x = -5/3 or -1

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