Q: What is 3x2 plus 8x plus 5?

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-8x + 3x2 - 3

3x2+13x-10 = (3x-2)(x+5) when factored

8x + 5 = 25(- 5 from both sides)8x = 20(divide both sides by 8)x = 2.5

If you mean -3(x+5) = 8x+18 then -3x-15 = 8x+18 and the value of x works out as -3

- 8x + 8x = 0 so question is meaningless.

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x2+8x = -3x2+5 4x2+8x-5 = 0 (2x+5)(2x-1) = 0 x = -5/2 or x = 1/2

(x + 1)(3x + 5)

-8x + 3x2 - 3

If you mean: 3x2+8+5 = 0 Then it crosses the x axis at points -1 and -5/3

5 - 8x + 3x2 = 3x2 - 8x + 5 (since the sign of the second term is negative, then 5 can be factored as (-1)(-5)) = (3x - )(x - ) (try to put 1 or 5 to the empty places, in order to obtain -8x) = (3x - 5)(x - 1)

In general, no.

two negative

Assuming the 2 is meant to be a square this is the form: x2 - 3x2 = -2x2 + 8x + 5

Twice. Between negative two and negative one.

2x^2 + 8x + 3 = 0

The sum 6 (3x^2) + 8x -3 plus 3 (3x^2) - 7x + 2 = 27 x^2 + x -1

8x plus 4y equals 5 is 8x + 4y = 5.