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How many roots does 3x2 plus 8x plus 3 have?

Updated: 8/19/2019
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13y ago

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two negative

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13y ago
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Q: How many roots does 3x2 plus 8x plus 3 have?
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Factor the trinomal -8x plus 3x2 - 3?

-8x + 3x2 - 3


X2 - 3 equals -3x2 plus 8x?

In general, no.


X2 plus 8x equals -3x2 plus 5?

x2+8x = -3x2+5 4x2+8x-5 = 0 (2x+5)(2x-1) = 0 x = -5/2 or x = 1/2


How to factor 3x2 plus 8x plus 5?

(x + 1)(3x + 5)


3x2 plus 8x plus 4 has two complex roots?

3x^2 + 8x + 4 = (x+2) (3x+2) x = -2 x = -2/3 So there are no complex roots, they are real. You can test this by b^2 - 4ac if greater than 0, it is real if equal, there will be 2 identical roots. if less than 0 you get imaginary roots.


How many times does 3x2 plus 8x plus 5 touch or cross the x axis?

If you mean: 3x2+8+5 = 0 Then it crosses the x axis at points -1 and -5/3


How many times does the graph of 3x2 plus 8x plus 5 cross the x-axis?

Twice. Between negative two and negative one.


Put the equation in the form ax2 plus bx plus c equals 0 x2-3 equals 3x2 plus 8x?

2x^2 + 8x + 3 = 0


What is (6(3x2) plus 8x-3) plus (3(3x2)-7x plus 2) simplified?

The sum 6 (3x^2) + 8x -3 plus 3 (3x^2) - 7x + 2 = 27 x^2 + x -1


What is 3x2 plus 8x plus 5?

= (3x + 5)(x + 1) so x = -5/3 or -1


What are the rational roots of 3x3 plus x2-8x plus 6?

I do not believe that there are any rational roots.


What is 2(4x3-3x2-8x) completlely factored?

It is 2x*(4x^2 - 3x - 8). The quadratic cannot be factorised: it has no rational roots.