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That trinomial is unfactorable (the roots are not integers).

Q: How do you factor the trinomial 6p2-3p-2?

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x + 8orx - 4

34-132

bobo ka kasi patal

factor the trinomial 16x^2+24x+9

(x+8)(x-5)

Related questions

just like factoring any other trinomial.

(y10 + 2y5z3 + 4z6)

You would factor out -1 (a) from a trinomial in an equation such as -a^2 +30a - 2a + 60 after the middle term has been separated. The final answer of this trinomial would then be (a-30) (a-30).

That is the linear part.

A factor of a perfect square trinomial is eithera number that is a factor of each term of the trinomial,a binomial that is a factor of the trinomial, ora product of the above two.For example, consider 4x2 + 8x + 4It has the factors2 or 4,(x + 1) or2x+2 = 2*(x+1) or 4x+4 = 4*(x+1)

x + 8orx - 4

34-132

vbh

(3x - y)(3x - 5y) and (2x + 1)(2x + 11)

The factors of that trinomial are (x - 13) and (x + 3) . Neither of them appears below.

bobo ka kasi patal

It's not enough to copy the question off the test. If you don't tell us what the trinomial is, we can't factor it for you.