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(x+8)(x-5)

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Not a polynomial

Q: Factor the trinomial below Enter each factor as a polynomial in descending order?

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(x + 8)(x - 5)

(5x - 1)(x + 6)

Start by looking for a common factor. Separate this factor, then factor the remaining polynomial.

It is x^2 -4 = (x-2)(x+2) when factored and it is the difference of two squares

That trinomial is unfactorable (the roots are not integers).

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