Wiki User
∙ 2010-05-17 12:53:31(x+8)(x-5)
Wiki User
∙ 2010-05-17 12:53:31BigBossPeso
(x + 8)(x - 5)
(5x - 1)(x + 6)
Start by looking for a common factor. Separate this factor, then factor the remaining polynomial.
That trinomial is unfactorable (the roots are not integers).
It is x^2 -4 = (x-2)(x+2) when factored and it is the difference of two squares
(x + 8)(x - 5)
(x + 2)(x - 9)
It's not enough to copy the question off the test. If you don't tell us what the trinomial is, we can't factor it for you.
-((x + 2)(x - 9))
(X+9)(x-2)
(5x - 1)(x + 6)
(x + 2)(x - 8)
(x - 3)(x + 6)
-70
(x + 2)(x - 7)
(5x + 2)(x + 1)
(x-3) (x+5)