x**2-2x-8
Multiply first 2 terms:
1*-8=-8
Find factors that add up to second term:
-2, 4 --> -2+4 = 2
-4,-2 --> -4+2 = -2
Rewrite:
x**2+2x-4x-8
Factor sets of terms
x**2+2x=x(x+2)
-4x-8=-4(x+2)
x**2+2x-4x-8 = x(x+2)-4(x+2)
Factor
x(x+2)-4(x+2) = (x+2)(x-4)
(x+8)(x-5)
(x + 8)(x - 5)
(5x - 1)(x + 6)
Start by looking for a common factor. Separate this factor, then factor the remaining polynomial.
It is x^2 -4 = (x-2)(x+2) when factored and it is the difference of two squares
(x+8)(x-5)
(x + 8)(x - 5)
(x + 2)(x - 9)
(5x - 1)(x + 6)
(x + 2)(x - 8)
(x + 2)(x - 7)
-((x + 2)(x - 9))
(x - 3)(x + 6)
(5x + 2)(x + 1)
-70
(X+9)(x-2)
(x - 4)(x - 11)