x2(x3 + 1) is the best you can do there.
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Need to factor under radical cubic root[X5} cubic root[X2 * X3] now bring out the X3 X*cubic root[X2] -----------------------
1.6667
x^5 - x^3 + x^2 - 1 = (x - 1)(x + 1)(x + 1)(x^2 - x + 1)
(x1+x2+...+x5)/5 = 34 (x1+x2+...+x5)= 5 * 34 = 170 [(x1+x2+...+x5) + x6]/6 = 35 170 + x6 = 6*35 = 210 x6 =210-170=40 Answer is 40
The additive inverse is x5 + 2x - 2.