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Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.?
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
Find 3 consecutive numbers where the product of the smaller two numbers is 37 less than the square of the largest number?
11,12,13
Find 3 consecutive odd numbers where the product of the smaller two numbers is 34 less than the square of the largest number?
3, 5, 7
What are 3 consecutive even numbers where the product of the smaller two numbers is 52 less than the square of the largest number?
6, 8, and 10. To figure this one out, it is trial and error, so pick random numbers. 4x6=24 8x8=64, difference of 40, not big enough. 6x8=48 10x10=100 difference of 52. So, the right answer is 6, 8, and 10.
Find 4 consecutive even integers where the product of the two smaller numbers is 56 less than the product of the two larger numbers?
4,6,8,10ok, that's kool, now what the hell is the answer to this mind blower?!?!The square of 9 more than a number is equal to 9 more than the square of the number What is the number? the answer is 10,8,6 and 4
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.?
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
What are 3 consecutive numbers where the product of the 2 smaller numbers is 19 less than the square of the largest number?
5,6,7
Find 3 consecutive numbers where the product of the smaller two numbers is 37 less than the square of the largest number?
11,12,13
Find 3 consecutive even numbers where the product of the smaller two numbers is 64 less than square of the largest number?
8,10,12
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number?
Let the numbers be ;- n, n+1, n+2. Hence n(n+1) is 19 less than (n+2)^(2) It follows;- n(n+1)+ 19 = (n+2)^(2) Multiply out the brackets. n^(2) + n + 13 = n^(2) + 4n + 4 Collect 'like' terms. n^(2) - n&(2) + 4n - n = 13 - 4 Add 3n = 9 n = 3 n+ 1 = 4 n +2 = 5 Hence 3,4, & 5 are the consecutive numbers.
Find 3 consecutive numbers where the product of the smaller two numbers is 28 less than the square of the largest number?
8, 9, and 10
Find 3 consecutive numbers where the product of the smaller two numbers is 52 less than the square of the largest number?
16, 17 and 18
Find three consecutive numbers where the product of the smaller two numbers is 40 less than the square of the largest number?
12, 13 and 14
What are the 3 consecutive odd numbers where the product of the smaller two numbers is 22 less than the square of the largest number?
1, 3, 5
Find three consecutive numbers where the product of the smaller two numbers is 46 less than the square of the largest number?
14, 15, 16
Find 3 consecutive even numbers where the product of the smaller two numbers is 40 less than the square of the largest number?
4, 6, and 8
Find 3 consecutive even numbers where the product of the smaller two numbers is 64 less than the square of the largest number?
8, 10, 12
