This is easily solved by using two equations in 2 unknowns and solving the system. x + y = 111 x - y = 43 If have not yet had the pleasure of studying algebra and the answer is important to you, you could hope the numbers are positive integers and try all pair of numbers whose sum is 43: 1,42 2,41 3,40 and so on, until you find a pair whose difference is 43.
linear pair ^^
The inverse of an ordered pair (a,b) is the pair (b,a). So you simply switch the order.
It is the distance to the right of the origin, which is the point whose coordinates are (0,0).
One possible pair is: 2+sqrt(3) and 5-sqrt(3).
23 * 16 = 368
2 and 1 .their sum is 3 .difference is 1
If you are looking for two prime numbers whose difference is 1, then the numbers have to be 1 & 3.
They are 16+23 = 39
rtyuik
No because 137 is a prime number whose only factors are itself and one
There are infinitely many pairs of numbers whose difference is equal to the sum of 538 and 259 (which is 797). One such pair is 420 and 1217. Another pair is 0 and 797.
5 and 15
Factor pairs for 18 include 1&18, 2&9, and 3&6. Only one of these pairs adds up to 11.
The first thing to do is find the factors of 6. These are 1, 2, 3 and 6. They can be paired up as 1 and 6, and 2 and 3. One of the numbers in the pair has to be negative, because they need to multiply to make -6. Also, because they need to sum to plus 1 (and one is negative) we need the factor pair that has a difference of 1. Thus the answer has to be 3 and -2.
10 and 28
They are: 2 and 140