The first thing to do is find the factors of 6. These are 1, 2, 3 and 6. They can be paired up as 1 and 6, and 2 and 3. One of the numbers in the pair has to be negative, because they need to multiply to make -6. Also, because they need to sum to plus 1 (and one is negative) we need the factor pair that has a difference of 1. Thus the answer has to be 3 and -2.
One such set is {-4, 5}.
a2+16 cannot be factored. There are no two numbers whose product is 16 and whose sum is 0.
19
-8
17 and 3 are two prime numbers whose sum is 20. Their product is 51.
One such set is {-4, 5}.
a2+16 cannot be factored. There are no two numbers whose product is 16 and whose sum is 0.
find two positive numbers whose product is a maximum. 1.) the sum is s.
19
31
There are 3 whose sum is 45 whose sum is 57 whose sum is 69 whose sum is 711 whose sum is 813 whose sum is 915 whose sum is 1017 whose sum is 1119 whose sum is 1219 whose sum is 1317 whose sum is 1415 whose sum is 1513 whose sum is 1611 whose sum is 179 whose sum is 187 whose sum is 195 whose sum is 203 whose sum is 211 whose sum is 22.
-8
17 and 3 are two prime numbers whose sum is 20. Their product is 51.
The three consecutive numbers whose sum and product are the same are 1, 2, and 3.
7 and 6
19
-3 and -4