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How would you go about solving this direct variation question and what is the answer- If P varies directly as the square of Q and the constant of variation is 6 what is the value of P when Q equals 12?
Costigan4
If P varies directly with the square of Q then the equation would be in the form of P = kQ2, where k is the constant of variation so the new equation would be: P = 6Q2, so when Q = 12 we have P=6*122, or P = 864
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