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If P varies directly with the square of Q then the equation would be in the form of P = kQ2, where k is the constant of variation so the new equation would be: P = 6Q2, so when Q = 12 we have P=6*122, or P = 864

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It is: y-4 = 9(x-5) => y = 9x-41 Or as: 9x-y-41 = 0. Another version of the standard form of a linear equation in coordinates x and y is y = s x + k, where s is the slope and k is a constant. In this question, the slope s is directly given, as is the value of y at the point where x = 5 so that- 44. The slope is always the coefficient of x in this standard form, and the constant k can be determined by solving the equation for the coordinates of the given point: When x = 5, y = (9 X 5) + k, and y(5) is stated by the question to be 4. 9 X 5 equals 45; therefore to obtain the right value for k, 45 + k =4 or k = - 41. The standard form of the equation is therefore y = 5x - 41.

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