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How can you find the distance between two numbers on a number line?
Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.
How do you find the shortest distance between two parallel lines?
The shortest distance between 2 parallel lines is a perpendicular drawn between 2 parallel lines the diagram shows it clearly 1 parallel line ------------------------------------|-------------------------------------------------------------------- | | | the vertical line is the shortest distance | | ------------------------------------|------------------------------------------------------------------- 2nd parallel line
Find the distance between the points -2 -10 and 10 6?
The sq.root of 122+162=20
Find the distance between points -6 1 and 10 -8?
If d is the distance between them, then d2 = (-6 -10)2 + (1 - (-8))2 = (-16)2 + 92 =256 + 81 = 337 so d = sqrt(337) = 18.36
What is the distance between points (-6 1) and (-2 -2)?
Points: (-6, 1) and (-2, -2) Distance: 5 units
What is the distance between the points (37) and (1516) on a coordinate plane?
To find the distance between the points (3, 7) and (15, 16) on a coordinate plane, you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Plugging in the values, ( d = \sqrt{(15 - 3)^2 + (16 - 7)^2} = \sqrt{12^2 + 9^2} = \sqrt{144 + 81} = \sqrt{225} = 15 ). Therefore, the distance between the points is 15 units.
What is the distance between 15 and negative 2?
13
Explain how to find the distance between the points (28-17) and (-15-17) on a coordinate plane?
the first point is x = 28 and y = -17. The second point is x = -15 and y = -17. Since both points have the same y coordinate then the points are on a straight horizontal line and distance is the difference of the x coordinates, or 28 - (-15) = 43
Find the distance between (6, -2) and (1, -2)?
5
Find the distance between the points: (-4, 15) and (1, 3)?
13 The distance between 2 points in a cordinate space is SQRT ((x2 -x1)2 + (y2- y1)2) Hence the answer to your question would be square root of (1-(-4))2 + (3-15)2 which would be square root of (25 + 144) or square root of (169) which is nothing but 13!!!
Find the distance between the points -2 2 and -2 2?
0 0
Find the distance between the points with the given coordinates (-2 5) and (-2 0).?
To find the distance between the points (-2, 5) and (-2, 0), we can use the distance formula. Since both points have the same x-coordinate (-2), the distance is simply the difference in their y-coordinates: |5 - 0| = 5. Therefore, the distance between the two points is 5 units.
Find the distance between the points-2 -10 and -8 -2?
10
Find the distance between the points 2 2 and -1 -6?
8.54
What is the distance between -14 -6 and 1 -14?
To find the distance between the points (-14, -6) and (1, -14), you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Substituting the values, ( d = \sqrt{(1 - (-14))^2 + (-14 - (-6))^2} = \sqrt{(15)^2 + (-8)^2} = \sqrt{225 + 64} = \sqrt{289} = 17 ). Therefore, the distance between the two points is 17 units.
Find the Distance between 2 2 5 -1?
To find the distance between two points in 3D space (x1, y1, z1) and (x2, y2, z2), use the distance formula: Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2) Substitute the coordinates into the formula to find the distance.
Find the distance between (-2 -3) and (-5 1).?
You can get distance and hours and directions from Mapquest.com
