(8-2)2+(-4-15)2 = 397 and the square root of this is the distance which is
19.925 rounded to 3 decimal places
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Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.
The shortest distance between 2 parallel lines is a perpendicular drawn between 2 parallel lines the diagram shows it clearly 1 parallel line ------------------------------------|-------------------------------------------------------------------- | | | the vertical line is the shortest distance | | ------------------------------------|------------------------------------------------------------------- 2nd parallel line
The sq.root of 122+162=20
If d is the distance between them, then d2 = (-6 -10)2 + (1 - (-8))2 = (-16)2 + 92 =256 + 81 = 337 so d = sqrt(337) = 18.36
Points: (-6, 1) and (-2, -2) Distance: 5 units