10
Points: (-7, -2) and (4, -4) Slope: -2/11
Rise = 8 - (-3) = 11 Run = -2 - 4 = -6 So ratio = -11/6
28 11 points in 1 quarter because 44/4 = 11 and the fraction is 11 over 1!
The question makes no sense.. you can easily find the sum of integers between 1 and 300 but what does 11 or 13 have to do with it.
find the benchmark for the number6,000
20
To find the distance between the points (3, -8) and (3, -19), you can use the distance formula, which is (d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}). Substituting the points into the formula: (d = \sqrt{(3 - 3)^2 + (-19 - (-8))^2} = \sqrt{0 + (-11)^2} = \sqrt{121} = 11). Thus, the distance between the points is 11.
11 points
If you mean points of (21, 16) and (9, 11) then the distance works out as 13
If you mean points of (21, 16) and (9, 11) then the distance works out as 13
To find the distance between the points (5, 35) and (11, 43) in the xy-plane, you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Plugging in the values, we get ( d = \sqrt{(11 - 5)^2 + (43 - 35)^2} = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10 ). Therefore, the distance between the two points is 10 units.
It is the square root of (-4-11)2+(17-17)2 which works out as 15.
If you mean points of (1, -2) and (-9, 3) then the distance is about 11 units using the distance formula
To find the distance between the points (80, 55) and (20, 44), we can use the distance formula: [ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ] Plugging in the coordinates, we get: [ d = \sqrt{(20 - 80)^2 + (44 - 55)^2} = \sqrt{(-60)^2 + (-11)^2} = \sqrt{3600 + 121} = \sqrt{3721} = 61 ] Thus, the distance between the points is 61 units.
Distance2 = (21-9)2 + (16-11)2 = 169 and the square root of this is the distance which is 13 units
If you mean points of (1, -2) and (-9, 3) then it works out as about 11
If you mean endpoints (-1, -3) and (11, -8) then by using the distance formula the length between the points is 13 units