x + 5y = 0
Subtract 5y from each side of the equation, just to put 'x' and 'y' on opposite sides.
x = -5y
This is interesting. If EITHER 'x' OR 'y' is zero, then the other one is also zero.
The only place on the graph where that is true is the origin. So the line goes through the origin,
and the 'x' and 'y' intercepts are both zero.
3x-9y-27
They will be on the horizontal x axis of the graph (look for the x-intercepts).
One.
Draw the axes. Plot the two intercepts. Draw a line connecting the two points
Graph the equation then find the x intercepts.
for the equation:5x + 10y = 20, the two intercepts are:x = 0 , y = 2 or (0,2)y = 0 , x = 4 or (4,0)The graph is a straight line passing through the two intercepts (0,2) and (4,0)
The slope of the graph of that equation is -1.
Using the quadratic equation formula: x = -1/4 and x = 2/3
3x-9y-27
They will be on the horizontal x axis of the graph (look for the x-intercepts).
Just swap the letter around in the formula that you are given!
Equations don't have y-intercepts, but their graphs may. The y-intercept of the graph of the equation in this question is 0.7 .
One.
No; it means draw the curve.
It has a complete lack of any x-intercepts.
Draw the axes. Plot the two intercepts. Draw a line connecting the two points
The result will be a plane that intercepts the x-, y-, and z-axes at +9, +6, and +3, respectively.