Draw the axes. Plot the two intercepts. Draw a line connecting the two points
The graph showed the results from his experiment. You can graph the data points to see what type of curve your equation defines.
By using the formula for a straight line equation graphed on the Cartesian plane by means of the x and y axes.
Verticle line test man. If it intersects two points it is its not a function. if it hits one point it is a function. and im currently looking up to see how it is a equation...
You could graph this Polynomial by using substution to solve for two points..which will define a line. If x=16, then y=0, If x=0, then y=8. Graph this line and you have the solution set for the equation.
Normally on the Cartesian plane using as for example the straight line equation y = mx+c whereas m is the gradient or slope and c is the y intercept.
It is a line. There are many ways to graph it using intercepts etc. But, you can pick some x points, plug them in your equation, and find the corresponding y point, The graph those (x,y) values
Using the quadratic equation formula: x = -1/4 and x = 2/3
Your x and y intercepts give you two points on the line of the graph. Use these two points in the slope equation m = (y2-y1)/(x2-x1), and that gives you the slope.
Yes it can. A linear equation in the form of y=mx+b can always be graphed used the x and y intercepts.
To find the intercepts of the equation (y = x^4 - 2x^2 - 8), we need to determine where the graph intersects the x-axis and y-axis. For the y-intercept, set (x = 0), yielding (y = -8), so the y-intercept is (0, -8). To find the x-intercepts, set (y = 0) and solve the equation (x^4 - 2x^2 - 8 = 0); this can be factored or solved using substitution methods, leading to the x-intercepts at approximately (x \approx 2.414) and (x \approx -2.414).
Yes - provided you allow both x and y intercepts.
It was the French mathematician Rene Descartes who created the coordinate plane.
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You calculate the coordinates using a fraction!
To determine the quadratic function from a graph, first identify the shape of the parabola, which can open upwards or downwards. Look for key features such as the vertex, x-intercepts (roots), and y-intercept. The standard form of a quadratic function is ( f(x) = ax^2 + bx + c ), where ( a ) indicates the direction of the opening. By using the vertex and intercepts, you can derive the coefficients to write the specific equation of the quadratic function.
-- Take the equation. -- Say to yourself, "At the x-intercept, y=0". Set 'y' equal to zero, solve the equation for 'x', and you have the x-intercept. -- Take the original equation again. -- Say to yourself, "At the y-intercept, x=0". Set 'x' equal to zero, solve the equation for 'y', and you have the y-intercept.
To find the intercepts of a quadratic equation in the standard form ( y = ax^2 + bx + c ), the y-intercept can be found by evaluating the equation at ( x = 0 ), which gives the point ( (0, c) ). For the x-intercepts, set ( y = 0 ) and solve the equation ( ax^2 + bx + c = 0 ) using the quadratic formula ( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). The resulting values of ( x ) will give the x-intercepts.