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Draw the axes. Plot the two intercepts. Draw a line connecting the two points

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15y ago

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How do you graph y x 2?

It is a line. There are many ways to graph it using intercepts etc. But, you can pick some x points, plug them in your equation, and find the corresponding y point, The graph those (x,y) values


What are the x-intercepts of the graph of y equals 12x2 - 5x - 2?

Using the quadratic equation formula: x = -1/4 and x = 2/3


How do you find slope using x and y intercepts?

Your x and y intercepts give you two points on the line of the graph. Use these two points in the slope equation m = (y2-y1)/(x2-x1), and that gives you the slope.


A linear equation cannot always be graphed by using intercepts alone?

Yes it can. A linear equation in the form of y=mx+b can always be graphed used the x and y intercepts.


What are the intercepts of the equation x4-2x2-8?

To find the intercepts of the equation (y = x^4 - 2x^2 - 8), we need to determine where the graph intersects the x-axis and y-axis. For the y-intercept, set (x = 0), yielding (y = -8), so the y-intercept is (0, -8). To find the x-intercepts, set (y = 0) and solve the equation (x^4 - 2x^2 - 8 = 0); this can be factored or solved using substitution methods, leading to the x-intercepts at approximately (x \approx 2.414) and (x \approx -2.414).


Can all the linear equations be graph using the intercept?

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What mathematician invented how to graph a line using intercepts?

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Graph the equation y -2x-4?

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How do you graph a linear equation with a fraction in it?

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How do you look at a graph and tell what the quadratic function i?

To determine the quadratic function from a graph, first identify the shape of the parabola, which can open upwards or downwards. Look for key features such as the vertex, x-intercepts (roots), and y-intercept. The standard form of a quadratic function is ( f(x) = ax^2 + bx + c ), where ( a ) indicates the direction of the opening. By using the vertex and intercepts, you can derive the coefficients to write the specific equation of the quadratic function.


How do you find the x and y-intercepts without using a graph?

-- Take the equation. -- Say to yourself, "At the x-intercept, y=0". Set 'y' equal to zero, solve the equation for 'x', and you have the x-intercept. -- Take the original equation again. -- Say to yourself, "At the y-intercept, x=0". Set 'x' equal to zero, solve the equation for 'y', and you have the y-intercept.


What is the formula to find the intercepts for a quadratic equation?

To find the intercepts of a quadratic equation in the standard form ( y = ax^2 + bx + c ), the y-intercept can be found by evaluating the equation at ( x = 0 ), which gives the point ( (0, c) ). For the x-intercepts, set ( y = 0 ) and solve the equation ( ax^2 + bx + c = 0 ) using the quadratic formula ( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). The resulting values of ( x ) will give the x-intercepts.