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Try 151,600! Permutations & Combinations.

P(n,r)=n!(n−r)!

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P(n,r)=n!/(n!-r!)r! ?

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Matthew Cotten

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3y ago

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Related Questions

What is the purpose of Pascal's triangle?

The Pascal's triangle is used partly to determine the coefficients of a binomial expression. It is also used to find the number of combinations taken n at a time of m things .


How can you figure out combinations in math?

If you have N things and want to find the number of combinations of R things at a time then the formula is [(Factorial N)] / [(Factorial R) x (Factorial {N-R})]


How do you find the number of combinations of 6 letters?

The number of combinations of 6 letters is 6! or 720.


How many combinations can be made from 32 items taken 4 at a time and how do you do it?

Do a web search for "permutations and combinations" to find the how. I make it 35,960.


Can you find the prime number combinations of 60?

They are: 2*2*3*5 = 60


How many different combinations can you make out of 5 different things?

5! = 120 ! means factorial. A factorial is the product of of the positive integers and equals the number of different combinations of a number. A factorial can be work out quite simply. Take the number 5. 5! = 5x4x3x2x1 = 120 So simply place the number you are trying to find out the combinations for first and then times it by all the numbers below. Some more examples would be: 8! = 8x7x6x5x4x3x2x1 = 4320 3! = 3x2x1 = 6 10! = 10x9x8x7x6x5x4x3x2x1 = 3,628,800 6! = 6x5x4x3x2x1 = 720 * * * * * An interesting introduction on factorials but totally misses the point of the question. A factorial generates permutations, not combinations! For combinations, abc is the same as acb, cab, bac, etc. The number of combinations of that you can make out of 5 things *including the null combination - ie nothing) is 25 = 32.


How many different combinations can someone make with 8 shirts and 6 pants?

To find the total number of different combinations of shirts and pants, you multiply the number of shirts by the number of pants. With 8 shirts and 6 pants, the calculation is 8 x 6, resulting in 48 different combinations.


How can you Find the number of combinations of objects in a set?

The number of R-combinations in a set of N objects is C= N!/R!(N-R)! or the factorial of N divided by the factorial of R and the Factorial of N minus R. For example, the number of 3 combinations from a set of 4 objects is 4!/3!(4-3)! = 24/6x1= 4.


How many 6 digit combinations are there in 20 numbers?

Oh, what a lovely question! Let's paint a happy little picture here. To find the number of 6-digit combinations using 20 numbers, we can use a simple formula: 20P6, which stands for 20 permutations taken 6 at a time. This gives us 387,600 unique combinations to explore and create beautiful patterns with. Just imagine all the possibilities waiting to be discovered!


How many 5 number combinations are there for 59 numbers?

Oh, what a lovely question! To find the number of 5-number combinations from 59 numbers, we can use a formula called combinations. It's like mixing colors on your palette! The formula is nCr = n! / r!(n-r)!, where n is the total numbers (59) and r is the number of selections (5). So, for 59 numbers choosing 5 at a time, there are 5,006,386 unique combinations waiting to be discovered! Just imagine all the beautiful possibilities that can come from those combinations.


The first two number are called in a subtracting problem?

Each part of a subtraction problem has a name. Remainder is what is left over (answer). When you are subtracting to compare two groups, or to find out how many more things are needed, this is called the difference. The number being taken away or subtracted is the subtrahend. The number from which the subtrahend is taken is called minuend.


What is a pascal's triangle used for?

It is used for lots of things such as finding out the total possible outcomes of tossing coins. You find the line that corresponds with how many coins you toss and add all the numbers in that line to get the number of possible outcomes also you can use it to find combinations and permutations and triangular numbers