The number of combinations of 6 letters is 6! or 720.
You can make six different combinations: 123 132 213 231 321 312. If you just need to know the number of combinations, you could find the answer without writing everything out by letting x represent the number of digits and calculating x*(x-1).
The first natural number is usually taken to be 1. The mean of one number is itself so the mean of the first natural number is 1.
The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.
Well, assuming you mean that there are 37 possible numbers you'd follow this method: c = 37 x (37-1) x(37-2) x (37-3) x ... (37-(n-1)) where c is the number of combinations and n is the number of numbers drawn. For example: if n = 6 then: c = 37 x 36 x 35 x 34 x 33 x 32 = 1673844480 combinations. There's normal a button on your calculator that'll do this for you.
The Pascal's triangle is used partly to determine the coefficients of a binomial expression. It is also used to find the number of combinations taken n at a time of m things .
If you have N things and want to find the number of combinations of R things at a time then the formula is [(Factorial N)] / [(Factorial R) x (Factorial {N-R})]
The number of combinations of 6 letters is 6! or 720.
Do a web search for "permutations and combinations" to find the how. I make it 35,960.
They are: 2*2*3*5 = 60
5! = 120 ! means factorial. A factorial is the product of of the positive integers and equals the number of different combinations of a number. A factorial can be work out quite simply. Take the number 5. 5! = 5x4x3x2x1 = 120 So simply place the number you are trying to find out the combinations for first and then times it by all the numbers below. Some more examples would be: 8! = 8x7x6x5x4x3x2x1 = 4320 3! = 3x2x1 = 6 10! = 10x9x8x7x6x5x4x3x2x1 = 3,628,800 6! = 6x5x4x3x2x1 = 720 * * * * * An interesting introduction on factorials but totally misses the point of the question. A factorial generates permutations, not combinations! For combinations, abc is the same as acb, cab, bac, etc. The number of combinations of that you can make out of 5 things *including the null combination - ie nothing) is 25 = 32.
Oh, what a lovely question! Let's paint a happy little picture here. To find the number of 6-digit combinations using 20 numbers, we can use a simple formula: 20P6, which stands for 20 permutations taken 6 at a time. This gives us 387,600 unique combinations to explore and create beautiful patterns with. Just imagine all the possibilities waiting to be discovered!
The number of R-combinations in a set of N objects is C= N!/R!(N-R)! or the factorial of N divided by the factorial of R and the Factorial of N minus R. For example, the number of 3 combinations from a set of 4 objects is 4!/3!(4-3)! = 24/6x1= 4.
Each part of a subtraction problem has a name. Remainder is what is left over (answer). When you are subtracting to compare two groups, or to find out how many more things are needed, this is called the difference. The number being taken away or subtracted is the subtrahend. The number from which the subtrahend is taken is called minuend.
It is used for lots of things such as finding out the total possible outcomes of tossing coins. You find the line that corresponds with how many coins you toss and add all the numbers in that line to get the number of possible outcomes also you can use it to find combinations and permutations and triangular numbers
there are 36 different combination possibilities. Try them all.
*inclusive: 74 = 2401 *exclusive: 7*6*5*4 = 840