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Try 151,600! Permutations & Combinations.

P(n,r)=n!(n−r)!

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P(n,r)=n!/(n!-r!)r! ?

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Matthew Cotten

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2y ago
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14y ago

10C6 = 10!/(10-6)!6! = 10*9*8*7/4*3*2*1 = 210 ways

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Q: Find the number of combinations of 10 things taken 6 at a time?
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Related questions

What is the purpose of Pascal's triangle?

The Pascal's triangle is used partly to determine the coefficients of a binomial expression. It is also used to find the number of combinations taken n at a time of m things .


How can you figure out combinations in math?

If you have N things and want to find the number of combinations of R things at a time then the formula is [(Factorial N)] / [(Factorial R) x (Factorial {N-R})]


How do you find the number of combinations of 6 letters?

The number of combinations of 6 letters is 6! or 720.


How many combinations can be made from 32 items taken 4 at a time and how do you do it?

Do a web search for "permutations and combinations" to find the how. I make it 35,960.


Can you find the prime number combinations of 60?

They are: 2*2*3*5 = 60


How many different combinations can you make out of 5 different things?

5! = 120 ! means factorial. A factorial is the product of of the positive integers and equals the number of different combinations of a number. A factorial can be work out quite simply. Take the number 5. 5! = 5x4x3x2x1 = 120 So simply place the number you are trying to find out the combinations for first and then times it by all the numbers below. Some more examples would be: 8! = 8x7x6x5x4x3x2x1 = 4320 3! = 3x2x1 = 6 10! = 10x9x8x7x6x5x4x3x2x1 = 3,628,800 6! = 6x5x4x3x2x1 = 720 * * * * * An interesting introduction on factorials but totally misses the point of the question. A factorial generates permutations, not combinations! For combinations, abc is the same as acb, cab, bac, etc. The number of combinations of that you can make out of 5 things *including the null combination - ie nothing) is 25 = 32.


How can you Find the number of combinations of objects in a set?

The number of R-combinations in a set of N objects is C= N!/R!(N-R)! or the factorial of N divided by the factorial of R and the Factorial of N minus R. For example, the number of 3 combinations from a set of 4 objects is 4!/3!(4-3)! = 24/6x1= 4.


The first two number are called in a subtracting problem?

Each part of a subtraction problem has a name. Remainder is what is left over (answer). When you are subtracting to compare two groups, or to find out how many more things are needed, this is called the difference. The number being taken away or subtracted is the subtrahend. The number from which the subtrahend is taken is called minuend.


What is a pascal's triangle used for?

It is used for lots of things such as finding out the total possible outcomes of tossing coins. You find the line that corresponds with how many coins you toss and add all the numbers in that line to get the number of possible outcomes also you can use it to find combinations and permutations and triangular numbers


How could you find the number of different combinations of 6 letters in a computer password?

there are 36 different combination possibilities. Try them all.


How can you find the total number of 4-number combinations possible from digits 1-7?

*inclusive: 74 = 2401 *exclusive: 7*6*5*4 = 840


How many 3 digit number can be using 123?

You can make six different combinations: 123 132 213 231 321 312. If you just need to know the number of combinations, you could find the answer without writing everything out by letting x represent the number of digits and calculating x*(x-1).