Do a web search for "permutations and combinations" to find the how. I make it 35,960.
6 different combinations can be made with 3 items
There are 5C3 = 10 combinations.
To calculate the number of possible combinations from 10 items, you can use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n is the total number of items (10) and r is the number of items you are choosing in each combination (which can range from 1 to 10). So, if you are considering all possible combinations (r=1 to 10), the total number of combinations would be 2^10, which is 1024.
There are 9C3 = 84 combinations.
If repeats are allowed than an infinite number of combinations is possible.
6 different combinations can be made with 3 items
There are 5C3 = 10 combinations.
If the order of the 3 matters, then there are (8 x 7 x 6) = 336 possibilities.If you don't care about the order of the 3, then there are 336/(3 x 2) = 56 distinct groups of 3 items.
To calculate the number of possible combinations from 10 items, you can use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n is the total number of items (10) and r is the number of items you are choosing in each combination (which can range from 1 to 10). So, if you are considering all possible combinations (r=1 to 10), the total number of combinations would be 2^10, which is 1024.
3 items each in 3 categories gives 3*3*3 = 27 possible combinations.
There is only one combination of ten items out of ten. For this question to have a non-trivial answer, either the ten items need to be selected from a larger number of items or a smaller number of items need to be selected from the ten items.
If order doesn't matter, 15 combinations and if order does matter, 360 combinations are possible.
There is no built in function in Excel to create a list of combinations of 39 items taken 5 at a time. However, the combin function will tell you how many combinations there are. For instance, combin(39,5) = 575757.
The answer is 60 different ways.Assuming that the items are not replaced after each pick, so on the first pick you could pick from five, the second four and the third from three.Achieved via nCr where n is the total number of choices, and r is the amount picked.5C1 * 4C1 * 3C1 = 60.
There are 120 combinations of 5 items, which can be calculated using the formula nCr = n! / r!(n - r)!.
There are 9C3 = 84 combinations.
It depends on the sizes of the combinations. For example, there is only one combination of 7 things out of 7, but there are 21 combinations of two items.