(3x + 7)(x - 3)
if you rearrange it, it becomes 4y + 8 = 3x2 -2x +1 4y = 3x2 -2x -7 y= (3x2 -2x -7)/4 which is a parabola
3x3 - 3x2 + 2x - 2 = 3x2(x - 1) + 2(x - 1) = (3x2 + 2)(x - 1)
x^5+2x^4+4x^2+2x-3
2x2 + x2 = 3x2
3x2-2x-21 = (3x+7)(x-3)
(3x + 7)(x - 3)
3(x2 - 2x + 3)
3X2 + 6X + 9 3(X2 + 2 + 3) -----------------------3 is a common factor of all terms
3x2 + 2x - 8 = 3x2 + 6x - 4x - 8 = 3x(x+2) - 4(x+2) = (3x-4)*(x+2)
x(3x-2)
if you rearrange it, it becomes 4y + 8 = 3x2 -2x +1 4y = 3x2 -2x -7 y= (3x2 -2x -7)/4 which is a parabola
3x2 + 2x + 3 + x2 + x + 1 = 4x 2+ 3x + 4
3x3 - 3x2 + 2x - 2 = 3x2(x - 1) + 2(x - 1) = (3x2 + 2)(x - 1)
If it is 3x2 + 4 = 2x + 4, then you can subtract 4 from both sides, and get 3x2 = 2x, and then x = 2/3
2x+3x2 = x (2+3x)
If the original is 2x + 3x2 + 6 + 5x3, you should rearrange the terms in order of exponent:5x3 + 3x2 + 2x + 6