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They are 12, 14 and 16.

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THEY ARE 12,14 AND

Q: Find three consecutive even integers that have the sum of 42.?

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16+18+20= 54

42, 44, 46.

No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.No.The sum of any number of even integers, consecutive or not, MUST be even. 219 is not even.

The numbers are -134, -132 and -130.

That isn't possible; three consecutive integers, or three consecutive positive integers, always have a sum that is a multiple of 3. In general, you can solve this quickly by trial and error. In this case, you will quickly find that a certain set of three consecutive integers will give you a sum that is TOO LOW, while the next-higher even integers will give you a sum that is TOO HIGH. You can also write an equation and solve it: n + (n + 2) + (n + 4) = 32. If you solve it, you will find that the solution is fractional, not integral.

Related questions

No. There is no set of three consecutive even integers with a sum of 40.

There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.

The three integers are 25, 26, and 27.

The even integers are 22, 24 and 26.

16+18+20= 54

The numbers are -18, -16 and -14.

The integers are -37, -36 and -35. Also, using consecutive even integers: -38, -36 and -34.

There are no consecutive even integers totaling 123 but there are two combinations of odd/even integers. They are 39, 41 and 43 as well as 40, 41 and 42.

10 12 14

You've come to the right place. The integers are: 2, 4, and 6

42, 44, 46.

They are -12, -10 and -8.