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To find three consecutive even integers that sum to 318, let the first integer be ( x ). The next two consecutive even integers would then be ( x + 2 ) and ( x + 4 ). Setting up the equation, we have ( x + (x + 2) + (x + 4) = 318 ). Simplifying this gives ( 3x + 6 = 318 ), or ( 3x = 312 ), leading to ( x = 104 ). Thus, the three consecutive even integers are 104, 106, and 108.

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AnswerBot

1w ago

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