20 & 3
28 and 36
12 and 24?
38-4=34
That's not possible... * * * * * How about -5 and 25?
22 and 26
29 and 36
37 and 21
20 & 3
28 and 36
12 and 24?
If you are looking for two prime numbers whose difference is 1, then the numbers have to be 1 & 3.
38-4=34
The answer is 39 and 19 (: hope this helps!
That's not possible... * * * * * How about -5 and 25?
Find the 2 numbers whose difference is two and whose sum is 480.
Let's denote the two numbers as x and y. From the given conditions, we can write the equations x + y = 64 and x - y = 12. By solving these two equations simultaneously, we can find the values of x and y. Adding the two equations eliminates y, giving 2x = 76, so x = 38. Substituting x back into one of the equations gives y = 26. Therefore, the two numbers are 38 and 26.