1.8+4=5.81.8x4=7.2
The numbers are 56 and 58.
Equal sums on both sides of the equation would be 29 + 29 = 58
To work this sort of problem out we need to divide the number given by the number of integers being sought (in that case two) 118 ÷ 2 = 59. So the two numbers will average 59 and they must be consecutive and even, that means that they must be 1 above and 1 below 59..... 58 and 60. 58 + 60 = 118
The numbers are 55, 56 and 57 OR 54, 56 and 58
trial and error; 5x7=35 9x9=82, difference of 47. not big enough difference. 7x9=63 11x11=121. differenence of 58, which is too big. sorry, but this means there is not answer.
33+25=58 32+26=58 14+44=58 etc......
76 + 58 = 134
37 and 21
There are no two consecutive integers that sum to 58. With two consecutive integers, one is even, the other is odd. The sum of an even number and an odd number is odd. 58 is even so cannot be the sum of two consecutive integers.
The two numbers whose sum is 58 and whose difference is 16 are 21 and 37.
a + b = 58 a - b = 16 Thus: 2a = 74 a = 37 b = 21
The sum of two numbers between 20-40 is 58. The difference is 12
10,12
58
65 + 58 = 123 65 - 58 = 7 The two numbers are therefore 58 and 65.
41 and 17
37 + 21 = 5837 - 21 = 16The two numbers therefore are 37 and 21.