0
y = 4x2 + 6 or
y = 4x2 + 0x + 6, where a = 4, b = 0 and c = 6
x-coordinate of the vertex = -b/2a = -0/2(4) = 0
y-coordinate of the vertex = 4(02) + 6 = 6
vertex is (0, 6)
(Or you can say: Since the vertex of y = x is (0, 0), and this graph is shifted 6 units upward in the y-axis, then the vertex of y = x + 6 would be (0, 0 + 6) or (0, 6)
Substitute 0 for y in order to find the roots.
y = 4x2 + 6
0 = 4x2 + 6
0 - 6 = 4x2 + 6 - 6
-6 = 4x2
-6/4 = 4x2/4
- 6/4 = x2
± √(-6/4) = x
± [√(6/4)]i = x x = [(1/2)√6]i or x = - [(1/2)√6]i
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What is evaluate six squared?
find out what 6 squared equals. which is 6 x 6 and that equals 36
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A squared plus b squared equals 26 where a equals b find a and b?
a=b=3.60555
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What is evaluate six squared?
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How do you find the axis of symmetry and vertex of y equals x squared plus 6x plus 10?
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Find the vertex of y equals x2 plus 10x plus 22?
-2-5
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Ten x squared minus 17 x equals 63?
actually,10x squared minus 17 equals 63 would come out to x equals the square root of 8.to work this out, you would first at 17 to both sides to get 10x squared alone.63 plus 17 equals 80. you now have 10x squared equals 80. then divide each side by ten to get x squared alone. 80 divided by 10 equals 8. now you have x squared equals eight. finally, to find x, you find the square root of each side. x squared's square root is x, and 8's square root is 2.82842712 but I'm assuming you only have to write out x=√8.but the other answer was a good try:)Improved Answer:-10x2-17x = 6310x2-17x-63 = 0When factored: (5x+9)(2x-7) = 0Therefore the roots of the quadratic equation are: x = -9/5 and x = 7/2
A squared plus 2a squared equals c squared?
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Find the vertex and equation of the directri for y2 equals -32x?
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
What is the formula a squared plus b squared equals c squared is used to find?
It is the pythagorean theorem. Used in finding the lengths of sides of right angled triangles.
