(0, 2, 15, 16, 17)
0+2+15+16+17 = 50
50/5 = 10
The median is 15, the mean is 10.
To achieve a mean of 10 with four numbers, their total must be 40. If the median is also 10, then when the numbers are arranged in order, the average of the two middle numbers must equal 10. This can be done with combinations of numbers such as 5, 5, 15, and 15, which satisfy both conditions: their mean is 10, their median is 10, and none of the numbers are 10.
4 4 6 6 10
10, 10, 20, 30, 30, 50.
If you mean a set of number like this; 4, 5, 7, 7, 8, 10 The median is 7 because that is the number is half way the beginning and end of the numbers when listed in increasing order.
Yes. In the set (9, 10, 11, 12, 13) 11 is the median and the mean.
There can be any number of sets to satisfy this. The median is the number in the middle and the mean is the average of the numbers. 2,4,6,8,30 is one possible set median = 6 mean = 10
1,1,10,11,12
The median is the middle number of a set when they are in order, least to greatest. If there is an even number of values, the median is the average of the middle two. Ex. 10, 17, 20, 45, 68 The median is 20. The mean is the average, which is the total of the numbers divided by how many numbers there are. Ex. 10, 17, 20, 45, 68 68 + 45 + 20 + 17 + 10 = 160 There are 5 numbers in this set. 160/5 = 32 The mean is 32.
The median is the middle number of any given set when they are in order, least to greatest. If there is an even number of values, the median is the average of the middle two. Ex. (10, 17, 20, 45, 68) The median is 20. In any given set, the mean is the average, which is the total of the numbers divided by how many numbers there are. Ex. (10, 17, 20, 45, 68) 68 + 45 + 20 + 17 + 10 = 160 There are 5 numbers in this set. 160/5 = 32 The mean is 32.
The "median" is the "number in the middle", if you sort the numbers. If (as here) the set has an even number of elements, you sort them, and then take the average (arithmetic mean) of the two numbers in the middle - in this example, the 5th and 6th number.
4 4 6 6 10
10, 10, 20, 30, 30, 50.
There cannot be such a set.If the mean is 10, the mode is 6 and the median is 9, the range must be at least 8.5.If the mode is 6, the median is 9 and the range is 8, the mean must be less than 9.8.
If you mean a set of number like this; 4, 5, 7, 7, 8, 10 The median is 7 because that is the number is half way the beginning and end of the numbers when listed in increasing order.
8, 9, 11 and 12
median = 8 mean = 7 mean < median.
The mean is 6.6. The median is 6. There is no mode.