Write this equation in slope-intercept form:
4x + 3y = 12 subtract 4x to both sides
3y = -4x + 12 divide by 3 to both sides
y = -(4/3)x + 4 since the y intercept is 4, then one point is (0, 4)
Let x = 3, then y = 0. So the second point is (3, 0)
Let x = -3, then y = 8. So the third point is (-3, 8)
Now that you have three points, plot them in a coordinate system and connect those points. The line that passes through these points is the graph of the function y = -(4/3)x + 4.
12-3y = 15 -3y = 15-12 -3y = 3 y = -1
Without an equality sign and not knowing the plus or minus values of 3y and 24 it can't be considered to be a straight line equation. But if you mean: 4x+3y = 24 then the coordinates of the line are (6, 0) and (0, 8)
6x - 3y = 12y intercept at x = 0 is y = 4x intercept at y = 0 is x = 2the graph is straight line passing through the two points: (0, 4) and (2, 0)
The equation for 3y + 3y = -1 is 3y + 3y = -1.
-8x+3y=12 3y = 8x+12 y = (8/3)x + 4 So it will be a line with slope 8/3 and y intercept of 4
-2x plus 3y equals 1
The equation 2x - 3y = 6 is a linear equation and a linear equation is always has a straight line as a graph
4x - 3y = 12-3y = -4x + 12y = (4/3)x - 4^plug this transformed version of the equation into your graphing calculator or do it out by hand.
12-3y = 15 -3y = 15-12 -3y = 3 y = -1
5y = 3y + 12 5y - 3y = (3y - 3y) + 12 2y = 12 y = 6
Without an equality sign and not knowing the plus or minus values of 3y and 24 it can't be considered to be a straight line equation. But if you mean: 4x+3y = 24 then the coordinates of the line are (6, 0) and (0, 8)
The slope of the graph of that equation is -1.
6x - 3y = 12y intercept at x = 0 is y = 4x intercept at y = 0 is x = 2the graph is straight line passing through the two points: (0, 4) and (2, 0)
-3y + z = 12
The equation for 3y + 3y = -1 is 3y + 3y = -1.
3x + y = c where c is any constant number of your choice.
-8x+3y=12 3y = 8x+12 y = (8/3)x + 4 So it will be a line with slope 8/3 and y intercept of 4