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Write this equation in slope-intercept form:
4x + 3y = 12 subtract 4x to both sides
3y = -4x + 12 divide by 3 to both sides
y = -(4/3)x + 4 since the y intercept is 4, then one point is (0, 4)
Let x = 3, then y = 0. So the second point is (3, 0)
Let x = -3, then y = 8. So the third point is (-3, 8)
Now that you have three points, plot them in a coordinate system and connect those points. The line that passes through these points is the graph of the function y = -(4/3)x + 4.
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What is the answer to the equation 12-3y equals 15?
12-3y = 15 -3y = 15-12 -3y = 3 y = -1
How do you graph the following equation 4x 3y24?
Without an equality sign and not knowing the plus or minus values of 3y and 24 it can't be considered to be a straight line equation. But if you mean: 4x+3y = 24 then the coordinates of the line are (6, 0) and (0, 8)
Graph the equation 6x-3y equals 12?
6x - 3y = 12y intercept at x = 0 is y = 4x intercept at y = 0 is x = 2the graph is straight line passing through the two points: (0, 4) and (2, 0)
What is the equation for 3y plus 3y equals -1?
The equation for 3y + 3y = -1 is 3y + 3y = -1.
Graph -8x plus 3Y equals 12?
-8x+3y=12 3y = 8x+12 y = (8/3)x + 4 So it will be a line with slope 8/3 and y intercept of 4
