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How many subsets are in the set 12345?
Number of subsets with no members = 1Number of subsets with one member = 5.Number of subsets with 2 members = (5 x 4)/2 = 10.Number of subsets with 3 members = (5 x 4 x 3 /(3 x 2) = 10.Number of subsets with 4 members = (5 x 4 x 3 x 2)/(4 x 3 x 2) = 5.Number of subsets with 5 members = 1Total subsets = 1 + 5 + 10 + 10 + 5 + 1= 32.A set with n elements has 2n subsets. In this case n = 5 and 25 = 32.The proof in the case that n = 5 uses a basic counting technique which say that if you have five things to do, multiply together the number of ways to do each step to get the total number of ways all 5 steps can be completed.In this case you want to make a subset of {1,2,3,4,5} and the five steps consist of deciding for each of the 5 numbers whether or not to put it in the subset. At each step you have two choices: put it in or leave it out.
How many subsets containing an odd number of elements does a set with 10 elements have?
Well, honey, a set with 10 elements will have 2^10 or 1024 subsets in total. Now, if we want to count just the subsets with an odd number of elements, we need to consider that for each element, you have the option of including it or not. So, you're looking at 2^9 or 512 subsets with an odd number of elements. Hope that clears things up for ya, darling.
How many different 10 element subsets can be made from a set of 15 sets?
That is the same as asking 15C10 which is 3003. It is 15! divided by (15-10)!(10!) This is 15x14x13x12x11 divided by 5x4x3x2x1 or divided by 120 or 360360=3003
Rectangle A is width 4 and length 8 so draw similar rectangle scale factor 2.5?
Draw a 10 x 20 rectangle.
How many subsets of set A that contain exacly 3 elements set A has 10 elements?
You have three choices at a time without repeats. To do this multiply 10x9x8=720. This will give you duplicates, so divide the result by 1x2x3.
How do you draw a Venn diagram for the intersection of 2 4 6 8 10 5 10 20 20 30 and 40?
be smart
Sort your times 5 and times 10 tables into a venn diagram?
No, you shouldn't because you really only use a venn diagram to compare and contrast. And 5s and 10s are really the same thing. For example 5x2=10 10x1=10.
What are the factors of 1000 on a Venn diagram?
1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, 500, 1000 Draw a circle around them.
How a Venn Diagram fits into the verification diagrams of both the immediate and mediate inferences?
if theres 40 students in all,17 ride on an airplane,28 ride on a boat,10 on a train,12 on both airplane and boat,4 ride on an airplane only,3 ride only on a train?show it on a venn diagram?
How many subsets are in a set with 5 members?
5 subsets of 4 and of 1, 10 subsets of 3 and of 2 adds up to 30.
How many subsets with an odd number of elements does a set of 10 elements have - Can you explain?
512 subsets
What are the subsets of real numbers and their relationship?
10
What is the 1st 10 multiples of 8 and the factor of 4 in a Venn Diagram?
Put 10, 20, 30, 40, 50, 60, 70 , 80 in the left circle. Put 1, 2, 4 in the right circle.
How many subsets are there in 50 elements?
A set with 50 elements has 250 subsets.
What is the gcf of 10 and 25 using venn diagram?
Put 2 and 10 in the left circle. Put 25 in the right circle. Put 1 and 5 in the space where they overlap. Since 5 is the greater of these two numbers, it is the GCF.
How do you make a venn diagram to show factors of 120 AND 150?
Draw overlapping circles. Put 4, 8, 12, 20, 24, 40, 60, 120 in the left circle. Put 25, 50, 75, 150 in the right circle. Put 1, 2, 3, 5, 6, 10, 15, 30 in the space where they overlap.
How would you make a Venn diagram to show the factors of 12 and 20 And what would be the common factors?
To create a Venn diagram showing the factors of 12 and 20, you would first list out all the factors of each number separately. The factors of 12 are 1, 2, 3, 4, 6, and 12, while the factors of 20 are 1, 2, 4, 5, 10, and 20. In the Venn diagram, you would place the factors of 12 in one circle and the factors of 20 in another circle, with the overlapping region representing the common factors, which in this case are 1, 2, and 4.
