We are looking for all sets with an odd number of elements in them. To find this we can use combinations. Adding up the odd combinations will total the subsets containing an odd number of elements.nCr where n=10 and r=(1,3,5,7,9)
10C1 + 10C3 + 10C5 + 10C7 + 10C9 = 512.
You could also take the total number of elements (2^10) and subtract all sets containing an even number of elements.
nCr where n=10 and r=(0,2,4,6,8,10)
1024-(1+45+210+210+45+1)=512
A set with n elements has 2n subsets. The number of proper subsets is one less, since 2n includes the set itself.
6
6
It depends on the set x. If set x is of cardinality n (it has n elements) then it has 2n subsets.
There are 6 such subsets of B.
512 subsets
The number of subjects will depend on what the elements of the set are. The number of subsets is 2a.
A set with n elements has 2n subsets. The number of proper subsets is one less, since 2n includes the set itself.
That means, figure out how many different subsets a set has. In general, if a set has n elements, it has 2n different subsets.
To get the number of subsets of size less than 2:Total number of subsets of a set of size N is 2NTotal number of subsets of size 1 is 100Total number of subsets of size 0 is 1Total number of subsets of size 2 is 100*99/2 = 4950Sum up: 100 + 1 + 4950 = 5051Subtract this from total subsets: 2100 - 5051 (Answer)
An element doesn't have subsets. Sets can have subsets.
8 subsets
A set with 9 elements has 2^9 = 512 subsets.
A set with 50 elements has 250 subsets.
A set with N elements has 2N subsets.
7.
If the universal set contains N elements then it has 2N subsets.