Well, honey, a set with "n" elements has 2 to the power of "n" subsets. So, if you've got a set with 5 elements, you're looking at 2 to the power of 5, which is 32 subsets. Math doesn't have to be boring, darling!
For example, if we have a set of numbers called A which has 3 members(in our case numbers): A={2,5,6} this set has 8 subsets (2^3) which are as follow: the empty set: ∅ {2},{5},{6} {2,5},{2,6},{5,6} {2,5,6}
A set of four elements has 24 subsets, since for every element there are two options: it may, or may not, be in a subset. This set of subsets includes the empty set and the original set, and everything in between.
Since there are 9 members in the given set there will be 29 = 512 subsets and I have neither the time nor inclination to list all 512 of them. A subset of the given set is any set all of whose members are members of the given set. This includes the null set. To start off: Null, {1}, {3}, {6}, etc {1,3}, {1,6}, {1,12}, etc {1,3,6}, (1,3,12}, etc etc
There are 16 subsets: {0, 5, 7, 12}, {0, 5, 7}, {0, 5, 12}, {0, 7, 12}, {5, 7, 12}, {0, 5}, {0, 7}, {0, 12}, {5, 7}, {5, 12}, {7, 12}, {0], {5}, {7}, {12}, and the empty set.
Number of subsets with no members = 1Number of subsets with one member = 5.Number of subsets with 2 members = (5 x 4)/2 = 10.Number of subsets with 3 members = (5 x 4 x 3 /(3 x 2) = 10.Number of subsets with 4 members = (5 x 4 x 3 x 2)/(4 x 3 x 2) = 5.Number of subsets with 5 members = 1Total subsets = 1 + 5 + 10 + 10 + 5 + 1= 32.A set with n elements has 2n subsets. In this case n = 5 and 25 = 32.The proof in the case that n = 5 uses a basic counting technique which say that if you have five things to do, multiply together the number of ways to do each step to get the total number of ways all 5 steps can be completed.In this case you want to make a subset of {1,2,3,4,5} and the five steps consist of deciding for each of the 5 numbers whether or not to put it in the subset. At each step you have two choices: put it in or leave it out.
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For example, if we have a set of numbers called A which has 3 members(in our case numbers): A={2,5,6} this set has 8 subsets (2^3) which are as follow: the empty set: ∅ {2},{5},{6} {2,5},{2,6},{5,6} {2,5,6}
The number of elements. A set with n elements has 2n subsets; for example, a set with 5 elements has 25 = 32 subsets.
Well, honey, the number of subsets in a set with 9 elements is given by 2 to the power of 9, which equals 512. So, there are 512 subsets in the set {1, 2, 3, 4, 5, 6, 7, 8, 9}. Don't worry, I double-checked it just for you.
A set of four elements has 24 subsets, since for every element there are two options: it may, or may not, be in a subset. This set of subsets includes the empty set and the original set, and everything in between.
Well honey, the set {1, 2, 3, 4, 5, 6, 7, 8, 9} has 9 elements, so it will have 2^9 subsets, including the empty set and the set itself. That's a grand total of 512 subsets. Math can be sassy too, you know!
How many subsets are there in 2 3 5 7 11 13 17 19 23?
(5 x 4 x 3)/(3 x 2) = 10
Since there are 9 members in the given set there will be 29 = 512 subsets and I have neither the time nor inclination to list all 512 of them. A subset of the given set is any set all of whose members are members of the given set. This includes the null set. To start off: Null, {1}, {3}, {6}, etc {1,3}, {1,6}, {1,12}, etc {1,3,6}, (1,3,12}, etc etc
For example, if we have a set of numbers called A which has 3 members(in our case numbers): A={2,5,6} this set has 8 subsets (2^3) which are as follow: the empty set: ∅ {2},{5},{6} {2,5},{2,6},{5,6} {2,5,6}
The set of rational numbers. 23.8 can be expressed as the fraction 119/5