We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.
As for example in the straight line equation of y=3x+5 the slope is 3 and the y intercept is 5
y=mx+b whatever multiplies x in this form is the slope
This is the first fundemental theorem of Calculus. The slope of a line is very important in your first calculus course. The slope tells you the rate of change. This means how much is the object change in height compared to its change in length. The slope of a line in Calculus is used as the first derivative. If you can take the slope of a line at one particular point you will find the answer to the derivative at this point. Remember this. You first equation on your graph is called your position equation. If you take the derivative of this equation it is called the velocity equation. The velocity equation is how much the position equation is sloping at each point. If you take the derivative of the velocity equation you will get the acceleration equation. The accerelation equation is how much the velocity is sloping at each point. You can take the derivative of the acceleration equation and this will give you the jerk equation. The jerk equation is not used in many applications and I have never used this equation in any of my 4 calculus classes.
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
first of all, i dont see how slope and yintercept has anything to do with shopping. usually in an equation, y= mx+b, m stands for slope, and b is the y-intercept. x and y are just x and y. If the equation is mixed up, and is not in y=mx+b format, you need to solve to get y on one side, the slope, x, and whatever the presented constant is (which is the y-intercept) on the other side. hope this helps.
y=-4
You have to differentiate the equation. The dy/dx is the slope.
An equation of a line requires two parameters. The slope, by itself, is not enough.
the slope formula is y=mx+b slope-intercept form of an equation of a line. where m=slope and b=the y-intercept
Use point-slope formula
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the slope is 0
Slope or gradient = (y2-y1)/(x2-x1)
With great difficulty because without an equality sign the given expression can't be considered to be a straight line equation
We know that the line passes through points (2, 2) and (0, 10) (since the y-intercept is 10).Using these two points, we can find the slope of the line,m = (10 - 2)/(0 - 2) = 8/-2 = 4/-1 = -4.Now by using the slope, m = -4, and the y-intercept, 10, we can write the equation of the line in the slope-intercept form, y = mx + b which isy = -4x + 10.