To graph the line 9x = y - 4 set up a table where on one side you have values for x and on the other you have values for y Set x to a range of values and calculate y (start with fairly obvious values like 0 and 1 and -1 continue with some extreme values like 100 and -100): x y
0 4
1 13
-1 -5
100 904
-100 -896 enter some of these value onto your graph paper (you could ignore the extremes they are very far out) You see that you get a line that is fairly steep (tat comes from the 9 as x factor) and the line crosses the x axis at 4 (that comes from the y-4) Answer: As the equation is that of a straight line, you only need to calculate the values of two points. The easiest are when x=0 (and y= 4) and when y=0 (and x=-(4/9))
-9/4 or -2.25
9x-4 = 7x+8 9x-7x = 8+4 2x = 12 x = 6
7x-4=9x+10-14=2xx=-7
The slope, or the change in y in respect to x, can be found by putting the equation into y = mx + b form. Y = (9/5) x - 4/5 The slope is m or (9/5). Any equation in y intercept form with that slope is parallel.
x = 4 is a straight line that is vertical when plotted on the xy graph, where y is the vertical axis and x is the horizontal axis. A vertical line has an infinite slope; the slope is infinity
-9/4 or -2.25
For the equation (9x^2)/(x^2+4)
9X=4 gives x=4/9
9x + 4 = 6 9x = 6 -4 9x = 2 x = 2/9
-9x + 4 = -50 -9x = -50 - 4 -9x = -54 -x = -6 x = 6.
9x-5x-2x = -4 2x = -4 x = -2
44 = 9x +8 36=9x 4=x
Centre of circle: (2, 1.25) Slope of line: 9/4 Equation of line: y-1.25 = 9/4(x-2) => 4y-5 = 9x-18 => 4y = 9x-13
9x-4 = 7x+8 9x-7x = 8+4 2x = 12 x = 6
7x-4=9x+10-14=2xx=-7
If: 9x = 21x-3 Then: x = 1/4 or 0.25
The line x = 4 is a verticle line because, in a standard x-y graph, where x increases to the right and y increases upwards, the graph x = 4 is all points y, where x is 4. That is a verticle line, with infinite slope.