Yes , it is possible because you can put the tips of each pencil together almost creating a star but they all touch within the center.
x= # of pencils that cost .45 y= # of pencils that cost .65 So now you need 2 equations for 2 variables: 15= x+y This equation is saying: 15 total pencils bought= pencils that cost .45 + pencils that cost .65 The second equation is: 7.75= .45x + .65y This equation is saying: total money spent (7.75)= price of pencils (.45) times # of pencils + price of pencils (.65) times # of pencils Then you combine these two equations, but first switch around the first equation to look like: y=15-x Then you replace the "y" in the second equation by putting in what y equals the first equation: 7.75= .45x + .65(15-x) Then distribute and solve for x: x = 10 Then enter 10 into the first equation for x to figure out y: y= 15- 10 y= 5 So your answer is-- Ray bought 10 pencils that cost .45 and 5 pencils that cost .65
Oh, dude, arranging 6 counters in equal rows is like a puzzle, man. So, if you're into math and stuff, there are 720 different ways you can do it. But hey, who's counting, right? Just go with the flow and arrange those counters however you like.
by 2 rows
The answer will be an incredibly huge number. There are a different number of windows, each window can refer to a different application, they can be of different sizes, they can be located at different positions.
i think it is
Yes it is. First, they must be sharpened to sharp points, then lay them in a circle with all of the points all joined in the center. Use a magnifying glass if you must ensure that each is touching all of the other six.
Pencils are not attracted to each other through magnetic or gravitational forces. The pencils may appear stationary because the forces of friction between the table and the pencils prevent them from moving. Additionally, the force created by your hands placing the pencils on the table may also keep them in place.
No, two pencils are not actually pulling on each other. The force of gravity between the two pencils is negligible due to their relatively small masses. Any perceived interaction between the pencils is a result of external forces acting on them, such as friction or air resistance, rather than a gravitational pull between the pencils themselves.
If pencils cost 0.26 each could you buy four pencils with 1.00?
288 pencils in 36 boxes, would mean 8 pencils in each box. If you had 288 pencils in each of 36 boxes, you would a total of 10,368 pencils.
The cost of p pencils is 20p.
When the food touches each other
You can arrange a meet between them. They can be comfortable with each other when they meet.
they exchange pp touches
4
3 pencils to each calculator
18 of them