4
by 2 rows
Make 4 equally spaced columns of 3 matchsticks. Across the top put the first row of 3 matchsticks and then put a further two rows of matchsticks equally spaced. This will form 9 small equal squares within a larger square.
8 rows of 6 students 6 rows of 8 students 4 rows of 12 students 3 rows of 16 students 2 rows of 24 students 1 row of 48 students
Since the columns of AT equal the rows of A by definition, they also span the same space, so yes, they are equivalent.
8
4
25
18
2 rows of 18 squares3 rows of 12 squares4 rows of 9 squares6 rows of 6 squares9 rows of 4 squares12 rows of 3 squares18 rows of 2 squares36 rows of 1 squareI would not count "1 row of 36 squares", because you only have a single row that cannot equal another row (there is only one rowafter all). If this is for homework, I would state your reasoning for excluding (or including) that set. Count all the options up, and you have 8 different ways you can arrange the rows with the exclusion.
18 Chairs into equal rows - 6 x 3 2 x 9 18 x 1
90000
Idk but i think you put them in 5 rows of 6 cause 6 times 5 = 30
Carefully arrange 12 rows with 8 coins in each row.
If you include a row or column of 1, the answer is 4: 1 by 6, 2 by 3, 3 by 2, and 6 by 1.
If you're making an outline of a square, then 16 counters. You have the 4 corner counters, each shared by 2 sides and then in between the corner counters there are 3 counters on each of the 4 sides (4*3 = 12). If you're filling the inside of the square with counters, then you have 5 rows of 5 = 25 counters.
You can have: 1 row of 36 2 rows of 18 3 rows of 12 4 rows of 9 or 6 rows of 6, so in total there are 5 ways.