3x-9y-27
They will be on the horizontal x axis of the graph (look for the x-intercepts).
One.
Draw the axes. Plot the two intercepts. Draw a line connecting the two points
Graph the equation then find the x intercepts.
-- If you know the general shape of a graph, and you can quickly determine the x- and y-intercepts, that's often enough information to make a pretty accurate sketch of the graph. -- In particular, if the equation is a linear one, then you know the graph will be a straight line; and then, as soon as you know the x- and y-intercepts, just draw the line between them and you don't need anything else ... that's your graph.
3x-9y-27
They will be on the horizontal x axis of the graph (look for the x-intercepts).
One.
No; it means draw the curve.
It has a complete lack of any x-intercepts.
Draw the axes. Plot the two intercepts. Draw a line connecting the two points
Graph the equation then find the x intercepts.
The X-Intercepts are the solutions. If you have an algebra calculator, you can usually find them by going to CALC>Zero>enter the left and right boundaries for each side.
The point where a graph intercepts the x axis may have several names. It could be called an x-intercept, a root, or a solution.It is at: (x, 0).
If "a" is negative then the graph is a cap. Find the x intercepts. Average the two x intercepts and substitute that into the equation it will give you the y.
The graph must have at least one intercept.