use the difference of two squares yule.
2(2x^2 + 2x - 5)
(2x + 5)(4x2 - 10x + 25)
if f(x) = x3 + 4x2 - 11x - 30, then yes, (x - 3) is indeed a factor. f(x) = x3 + 4x2 - 11x - 30 ∴ f(x) = (x - 3)(x2 + 7x + 10) ∴ f(x) = (x - 3)(x + 2)(x + 5)
4(x + 1)(x + 1)
2a3-16a2+30a Factor out 2a: 2a(a2-8a+15) (2a)(a-5)(a-3) This is the most factored form of this expression.
(4a - 3b)(4a + 3b)
4x2 - 9y Not factorable from what I see.
The GCF is 4x2.
4(4a2 - b2) 4(2a + b)(2a - b)
4x2-y2 = (2x-y)(2x+y)
GCF(28a5, 16a2) = 4a2.
If that's + 4x2, the answer is 2x(x2 + 2x - 4)
4x2+20x+25 (2x+5)^2
4x2-36x+81 (2x-9)(2x-9)
4x2 - 23xy + 15y2 = (4x - 3y)(x - 5y)
You would factor it in this way: 2 * 2 * x * x.