Depending on the missing operational sign, that's 2(x plus or minus 6)
4x2 - 2x - 12= 2x2 - x - 6= 2x2 - 4x + 3x - 6= 2x(x - 2) + 3(x - 2)= (x - 2)(2x + 3)
(2x - 5) is a binomial factor
2x2 - 72 would be factored into (2x - 12)(x + 6) or (2x + 12)(x - 6) To double check, multiply each pair: (2x - 12)(x + 6) = 2x2 + 12x - 12x - 72 = 2x2 - 72 (2x + 12)(x - 6) = 2x2 - 12x + 12 x - 72 = 2x2 - 72
2xx-5x-12 2*-12=-24 -24=-8*3 -8+3=-5 2xx-8x+3x-12 2x(x-4)+3(x-4) (2x+3)(x-4)
2x^(2) - 5x - 12 First write down all the factors of '2' & '12' 2 = 1,2 12 = 1,12; 2,6; 3,4 . From this we select two pairs of numbers, one pair from each coefficient, that add/multiply to '5' They are, 1,2 & 3,4 Hence -(2 x 4) + (1 x 3) = -8 + 3 = -5 Set up the brackets (2x 3)(x 4) Hence the signs are ( 2x + 3)(x - 4)
2x+12=2(x+6)
The GCF of 2x and 12 is 2.
(2x - 4)(2x + 3) The key is to look for all the factor pairs of 12.
6x2=12 2x-28=?
2(2x + 3)(x - 2)
As written, that's 2(x - 6) You may have meant 4x^2 - 2x - 12 which would be 2(2x + 3)(x - 2)
2x2 + 11x + 12 = 2x2 + 3x + 8x + 12 = x*(2x + 3) + 4*(2x + 3) = (2x + 3)*(x + 4)
(2x+3)(2x+4)
2x^(2) - 5x - 12 First write down all the factors of '2' & '12' 2 = 1,2 12 = 1,12; 2,6; 3,4 . From this we select two pairs of numbers, one pair from each coefficient, that add/multiply to '5' They are, 1,2 & 3,4 Hence -(2 x 4) + (1 x 3) = -8 + 3 = -5 Set up the brackets (2x 3)(x 4) Hence the signs are ( 2x + 3)(x - 4)
12
You can factor it, if you consider that simpler.
It can be. 2x is a factor of 4x.