Factor the equation and solve for x in each part. x3-4x2-12x Factor out an x right away x (x² - 4x - 12) factor the trinomial x (x - 6) (x + 2) now solve each for y=0 x=0, (x-6=0), (x+2=0) The zeroes (solutions) to the equation are {-2 0 6 }■
16 - a2
So the problem is: Solve: 4x2 - x = 3
4x2 - 9 = (2x + 3)(2x - 3)
use the difference of two squares yule.
If you can't factor it easily, use the quadratic formula.
4x2 - 9y Not factorable from what I see.
The GCF is 4x2.
4x2-y2 = (2x-y)(2x+y)
If that's + 4x2, the answer is 2x(x2 + 2x - 4)
Factor the equation and solve for x in each part. x3-4x2-12x Factor out an x right away x (x² - 4x - 12) factor the trinomial x (x - 6) (x + 2) now solve each for y=0 x=0, (x-6=0), (x+2=0) The zeroes (solutions) to the equation are {-2 0 6 }■
4x2 = -12x, divide both sides by 4x: x = -3
4x2+20x+25 (2x+5)^2
4x2-36x+81 (2x-9)(2x-9)
4x2 - 23xy + 15y2 = (4x - 3y)(x - 5y)
You would factor it in this way: 2 * 2 * x * x.
4x