(x + 12)(x - 8)
(3x - 4)(4x - 3)
The expression x2 + 1x - 12 can be factored out as (x - 3)(x + 4)
Depending on the missing operational sign, that's 2(x plus or minus 6)
(n - 4)(n - 12)
The other factor is 1.
12(m + 5)
12(b + 1)(b + 1)
2x+12=2(x+6)
(x + 6)(x + 2)
(3x+12)(5x+2)
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
3(3z + 4)
3(4 + q)
It is: 4(x+3)
You can factor it, if you consider that simpler.
There is no factor of the expression in the question.