2x^(2) - 5x - 12
First write down all the factors of '2' & '12'
2 = 1,2
12 = 1,12; 2,6; 3,4 .
From this we select two pairs of numbers, one pair from each coefficient, that add/multiply to '5'
They are, 1,2 & 3,4
Hence
-(2 x 4) + (1 x 3) = -8 + 3 = -5
Set up the brackets
(2x 3)(x 4)
Hence the signs are
( 2x + 3)(x - 4)
(x + 12)(x - 8)
(3x - 4)(4x - 3)
The expression x2 + 1x - 12 can be factored out as (x - 3)(x + 4)
Depending on the missing operational sign, that's 2(x plus or minus 6)
(n - 4)(n - 12)
The other factor is 1.
12(m + 5)
12(b + 1)(b + 1)
2x+12=2(x+6)
(x + 6)(x + 2)
(3x+12)(5x+2)
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
3(3z + 4)
You can factor it, if you consider that simpler.
3(4 + q)
It is: 4(x+3)
There is no factor of the expression in the question.